How to pass the password to su/sudo/ssh without overriding the TTY?

I'm writing a C Shell program that will be doing su or sudo or ssh. They all want their passwords in console input (the TTY) rather than stdin or the command line.

Does anybody know a solution?

Setting up password-less sudo is not an option.

expect could be an option, but it's not present on my stripped-down system.

Solution 1:

For sudo there is a -S option for accepting the password from standard input. Here is the man entry:

    -S          The -S (stdin) option causes sudo to read the password from
                the standard input instead of the terminal device.

This will allow you to run a command like:

echo myPassword | sudo -S ls /tmp

As for ssh, I have made many attempts to automate/script it's usage with no success. There doesn't seem to be any build-in way to pass the password into the command without prompting. As others have mentioned, the "expect" utility seems like it is aimed at addressing this dilemma but ultimately, setting up the correct private-key authorization is the correct way to go when attempting to automate this.

Solution 2:

I wrote some Applescript which prompts for a password via a dialog box and then builds a custom bash command, like this:

echo <password> | sudo -S <command>

I'm not sure if this helps.

It'd be nice if sudo accepted a pre-encrypted password, so I could encrypt it within my script and not worry about echoing clear text passwords around. However this works for me and my situation.

Solution 3:

For ssh you can use sshpass: sshpass -p yourpassphrase ssh user@host.

You just need to download sshpass first :)

$ apt-get install sshpass
$ sshpass -p 'password' ssh username@server

Solution 4:

For sudo you can do this too:

sudo -S <<< "password" command

Solution 5:

I've got:

ssh user@host bash -c "echo mypass | sudo -S mycommand"

Works for me.