The calling thread must be STA, because many UI components require this

Try to invoke your code from the dispatcher:

Application.Current.Dispatcher.Invoke((Action)delegate{
      // your code
});

If you make the call from the main thread, you must add the STAThread attribute to the Main method, as stated in the previous answer.

If you use a separate thread, it needs to be in a STA (single-threaded apartment), which is not the case for background worker threads. You have to create the thread yourself, like this:

Thread t = new Thread(ThreadProc);
t.SetApartmentState(ApartmentState.STA);

t.Start();

with ThreadProc being a delegate of type ThreadStart.

You can also try this

// create a thread  
Thread newWindowThread = new Thread(new ThreadStart(() =>  
{  
    // create and show the window
    FaxImageLoad obj = new FaxImageLoad(destination);  
    obj.Show();  
    
    // start the Dispatcher processing  
    System.Windows.Threading.Dispatcher.Run();  
}));  

// set the apartment state  
newWindowThread.SetApartmentState(ApartmentState.STA);  

// make the thread a background thread  
newWindowThread.IsBackground = true;  

// start the thread  
newWindowThread.Start();  

I suspect that you are getting a callback to a UI component from a background thread. I recommend that you make that call using a BackgroundWorker as this is UI thread aware.

For the BackgroundWorker, the main program should be marked as [STAThread].

Just mark your program Main method with the [STAThread] attribute and the error goes away! it's magic :)

Example:

class Program {
    [STAThread]
    static void Main(string[] args) {
    // My code here
    }
}