Shuffle two list at once with same order
Solution 1:
You can do it as:
import random
a = ['a', 'b', 'c']
b = [1, 2, 3]
c = list(zip(a, b))
random.shuffle(c)
a, b = zip(*c)
print a
print b
[OUTPUT]
['a', 'c', 'b']
[1, 3, 2]
Of course, this was an example with simpler lists, but the adaptation will be the same for your case.
Hope it helps. Good Luck.
Solution 2:
I get a easy way to do this
import numpy as np
a = np.array([0,1,2,3,4])
b = np.array([5,6,7,8,9])
indices = np.arange(a.shape[0])
np.random.shuffle(indices)
a = a[indices]
b = b[indices]
# a, array([3, 4, 1, 2, 0])
# b, array([8, 9, 6, 7, 5])
Solution 3:
from sklearn.utils import shuffle
a = ['a', 'b', 'c','d','e']
b = [1, 2, 3, 4, 5]
a_shuffled, b_shuffled = shuffle(np.array(a), np.array(b))
print(a_shuffled, b_shuffled)
#random output
#['e' 'c' 'b' 'd' 'a'] [5 3 2 4 1]
Solution 4:
Shuffle an arbitray number of lists simultaneously.
from random import shuffle
def shuffle_list(*ls):
l =list(zip(*ls))
shuffle(l)
return zip(*l)
a = [0,1,2,3,4]
b = [5,6,7,8,9]
a1,b1 = shuffle_list(a,b)
print(a1,b1)
a = [0,1,2,3,4]
b = [5,6,7,8,9]
c = [10,11,12,13,14]
a1,b1,c1 = shuffle_list(a,b,c)
print(a1,b1,c1)
Output:
$ (0, 2, 4, 3, 1) (5, 7, 9, 8, 6)
$ (4, 3, 0, 2, 1) (9, 8, 5, 7, 6) (14, 13, 10, 12, 11)
Note:
objects returned by shuffle_list()
are tuples
.
P.S.
shuffle_list()
can also be applied to numpy.array()
a = np.array([1,2,3])
b = np.array([4,5,6])
a1,b1 = shuffle_list(a,b)
print(a1,b1)
Output:
$ (3, 1, 2) (6, 4, 5)