How to extract HTTP status code from the RestTemplate call to a URL?

Use the RestTemplate#exchange(..) methods that return a ResponseEntity. This gives you access to the status line and headers (and the body obviously).

• getStatusCode()
• getHeaders()

If you don´t want to leave the nice abstraction around RestTemplate.get/postForObject... methods behind like me and dislike to fiddle around with the boilerplate stuff needed when using RestTemplate.exchange... (Request- and ResponseEntity, HttpHeaders, etc), there´s another option to gain access to the HttpStatus codes.

Just surround the usual RestTemplate.get/postForObject... with a try/catch for org.springframework.web.client.HttpClientErrorException and org.springframework.web.client.HttpServerErrorException, like in this example:

try {
    return restTemplate.postForObject("http://your.url.here", "YourRequestObjectForPostBodyHere", YourResponse.class);

} catch (HttpClientErrorException | HttpServerErrorException httpClientOrServerExc) {

    if(HttpStatus.NOT_FOUND.equals(httpClientOrServerExc.getStatusCode())) {
      // your handling of "NOT FOUND" here  
      // e.g. throw new RuntimeException("Your Error Message here", httpClientOrServerExc);
    }
    else {
      // your handling of other errors here
}

The org.springframework.web.client.HttpServerErrorException is added here for the errors with a 50x.

Now you´re able to simple react to all the StatusCodes you want - except the appropriate one, that matches your HTTP method - like GET and 200, which won´t be handled as exception, as it is the matching one. But this should be straight forward, if you´re implementing/consuming RESTful services :)