Milliliters of sulphuric acid used to prepare an acid

How many ml of 95% w/w sulphuric acid having a specific gravity of 1.820 should be used in preparing 2 liters of 10% w/v acid?

The answer is 115.67 ml of 95% I would like to know the solution. Thanks!

we have $95$ g of h2so4 in $100$ g of water that is $95$g in $54.95$ml of water that $172.88$g in $100$ml of water. Now we can calculate molarity of this solution which is $17.64M$. Now let $x$ml of such solution be taken. Also molarity of resulting solution is$1.020M$ thus using $M_1V_1=M_2V_2$ we have $x(17.64)=1.020 \times(2000 ml)$ thus $x=115.65$ml rounding error caused a deviation so that should work fine if you increase the accuracy.