Get TypeTag[A] from Class[A]
I have createOld
method that I need to override and I cannot change it. I would like to use TypeTag
to pattern match provided type in createNew
. The goal is to find out how to call createNew
from createOld
. My current understanding is that compiler doesn't have enough type information about A
in createOld
method if it doesn't already come with TypeTag[A]
.
object TypeTagFromClass {
class C1
class C2
// How to get TypeTag[A] needed by createNew?
def createOld[A](c: Class[A]): A = createNew ???
def createNew[A : TypeTag]: A = {
val result = typeOf[A] match {
case a if a =:= typeOf[C1] => new C1()
case a if a =:= typeOf[C2] => new C2()
}
result.asInstanceOf[A]
}
}
Solution 1:
It is possible to create a TypeTag
from a Class
using Scala reflection, though I'm not sure if this implementation of TypeCreator
is absolutely correct:
import scala.reflect.runtime.universe._
def createOld[A](c: Class[A]): A = createNew {
val mirror = runtimeMirror(c.getClassLoader) // obtain runtime mirror
val sym = mirror.staticClass(c.getName) // obtain class symbol for `c`
val tpe = sym.selfType // obtain type object for `c`
// create a type tag which contains above type object
TypeTag(mirror, new TypeCreator {
def apply[U <: Universe with Singleton](m: api.Mirror[U]) =
if (m eq mirror) tpe.asInstanceOf[U # Type]
else throw new IllegalArgumentException(s"Type tag defined in $mirror cannot be migrated to other mirrors.")
})
}
However, you don't really need full TypeTag
if you don't need to inspect generic parameters and full Scala type information. You can use ClassTag
s for that:
def createNew[A: ClassTag]: A = {
val result = classTag[A].runtimeClass match {
case a if a.isAssignableFrom(classOf[C1]) => new C1()
case a if a.isAssignableFrom(classOf[C2]) => new C2()
}
result.asInstanceOf[A]
}
Or with some implicit sugar:
implicit class ClassTagOps[T](val classTag: ClassTag[T]) extends AnyVal {
def <<:(other: ClassTag[_]) = classTag.runtimeClass.isAssignableFrom(other.runtimeClass)
}
def createNew[A: ClassTag]: A = {
val result = classTag[A] match {
case a if a <<: classTag[C1] => new C1()
case a if a <<: classTag[C2] => new C2()
}
result.asInstanceOf[A]
}
You can simplify that even further by using plain old Java newInstance()
method:
def createNew[A: ClassTag]: A = classTag[A].runtimeClass.newInstance().asInstanceOf[A]
This, of course, would only work if you don't need different constructor parameters for different classes.
Calling this createNew
from createOld
is much simpler than the one with TypeTag
s:
def createOld[A](c: Class[A]): A = createNew(ClassTag[A](c))