Irrationality of powers of $\pi$
Solution 1:
What Robin hinted at:
If $\pi^{n}$ was rational, then $\pi$ would not be transcendental, as it would be the root of $ax^{n}-b = 0$ for some integers $a,b$.
Irrationality of powers of $\pi$
Solution 1:
What Robin hinted at:
If $\pi^{n}$ was rational, then $\pi$ would not be transcendental, as it would be the root of $ax^{n}-b = 0$ for some integers $a,b$.