Split a string at uppercase letters
What is the pythonic way to split a string before the occurrences of a given set of characters?
For example, I want to split
'TheLongAndWindingRoad'
at any occurrence of an uppercase letter (possibly except the first), and obtain
['The', 'Long', 'And', 'Winding', 'Road']
.
Edit: It should also split single occurrences, i.e.
from 'ABC'
I'd like to obtain
['A', 'B', 'C']
.
Solution 1:
Unfortunately it's not possible to split on a zero-width match in Python. But you can use re.findall
instead:
>>> import re
>>> re.findall('[A-Z][^A-Z]*', 'TheLongAndWindingRoad')
['The', 'Long', 'And', 'Winding', 'Road']
>>> re.findall('[A-Z][^A-Z]*', 'ABC')
['A', 'B', 'C']
Solution 2:
Here is an alternative regex solution. The problem can be reprased as "how do I insert a space before each uppercase letter, before doing the split":
>>> s = "TheLongAndWindingRoad ABC A123B45"
>>> re.sub( r"([A-Z])", r" \1", s).split()
['The', 'Long', 'And', 'Winding', 'Road', 'A', 'B', 'C', 'A123', 'B45']
This has the advantage of preserving all non-whitespace characters, which most other solutions do not.