How do I get the size of a Linux or Mac OS X directory from the command-line? [duplicate]
Solution 1:
The BSD version of du
used in OS X reports size with 512-byte blocks -- the sizes are essentially rounded up to the next 512-byte value. This tells you the space on disk, which is larger than the amount of data. If you have a lot of small files, the difference can be large.
Here's an example.
This is the value with regular du
. It's in 512-byte blocks:
$ du -s
248 .
The -h
flag results in a more readable number, in kilobytes. As expected, it's half the number of 512-byte blocks:
$ du -hs
124K .
Finally, you can use find
and awk
to give you the sum of actual bytes in the files. This is kind of slow, but it works:
$ find . -type f -exec ls -l {} \; | awk '{sum += $5} END {print sum}'
60527
This value matches exactly the number reported by Finder's Get Info window. (There are no weird forks or xattrs in this set of files.) It's significantly smaller than the value reported by du
.
Here's how it works: it gets a list of all the files, and passes them to ls -l
; then awk
is used to count up the bytes. The -type f
flag is there so that only files (and not directories) get sent to ls
. Without that flag, it'll also send directory names to ls
, and each file will be listed twice : once as an individual file, and once as an item in the directory.
The GNU version of du
can give values in actual bytes instead of blocks. It's unfortunate that the BSD version of du
is not as flexible.
Solution 2:
Show the size of a single file
du -h path_to_a_file
Show the size of the contents of a directory, each sub-directory, and each individual file:
du -h path_to_a_directory
Show the size of the contents of a directory:
du -sh path_to_a_directory
Solution 3:
du - tells the disk use not the file size.
find . -type f -print0 | xargs -0 stat -f%z | awk '{b+=$1} END {print b}'
above terminal code (im on osx 10.6) offers for me the best result and is waaay faster than "find ... -exec"
a quick benchmark
time find . -type f -print0 | xargs -0 stat -f'%z' | awk '{b+=$1} END {print b}'
4744010970
real 0m0.086s
user 0m0.029s
sys 0m0.073s
time find . -type f -exec ls -l {} \; | awk '{sum += $5} END {print sum}'
4744010970
real 0m18.515s
user 0m2.929s
sys 0m9.339s