Using Tint color on UIImageView

I have my own subclass of UIButton. I add UIImageView on it and add an image. I would like to paint it over the image with a tint color but it doesn't work.

So far I have:

- (id)initWithFrame:(CGRect)frame
{
    self = [super initWithFrame:frame];
    if (self) {

        self.backgroundColor = [UIColor clearColor];
        self.clipsToBounds = YES;

        self.circleView = [[UIView alloc]init];
        self.circleView.backgroundColor = [UIColor whiteColor];
        self.circleView.layer.borderColor = [[Color getGraySeparatorColor]CGColor];
        self.circleView.layer.borderWidth = 1;
        self.circleView.userInteractionEnabled = NO;
        self.circleView.translatesAutoresizingMaskIntoConstraints = NO;
        [self addSubview:self.circleView];

        self.iconView = [[UIImageView alloc]init];
        [self.iconView setContentMode:UIViewContentModeScaleAspectFit];
        UIImage * image = [UIImage imageNamed:@"more"];
        [image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];
        self.iconView.image = image;
        self.iconView.translatesAutoresizingMaskIntoConstraints = NO;
        [self.circleView addSubview:self.iconView];
        ...

and on selection :

- (void) setSelected:(BOOL)selected
{
    if (selected) {
        [self.iconView setTintColor:[UIColor redColor]];
        [self.circleView setTintColor:[UIColor redColor]];
    }
    else{
        [self.iconView setTintColor:[UIColor blueColor]];
        [self.circleView setTintColor:[UIColor blueColor]];
    }  
}

What did I do wrong? (The color of the image always stays the same as it was originally.)

Solution 1:

Instead of this code:

[image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];

you should have:

image = [image imageWithRenderingMode:UIImageRenderingModeAlwaysTemplate];

Use this in Swift 4.1

image = UIImage(named: "name")!.withRenderingMode(.alwaysTemplate)

Solution 2:

You can also just set this on your asset. Make sure your image contains all white pixels + transparent.