Django: How to allow a Suspicious File Operation / copy a file
In Django, SuspiciousFileOperation can be avoid by read the file from external dir and make a tmp file within the project media then save in the appropriate file filed as below
import tempfile
file_name="file_name.pdf"
EXT_FILE_PATH = "/home/somepath/"
file_path = EXT_FILE_PATH + file_name
if exists(file_path):
#create a named temporary file within the project base , here in media
lf = tempfile.NamedTemporaryFile(dir='media')
f = open(file_path, 'rb')
lf.write(f.read())
#doc object with file FileField.
doc.file.save(file_name, File(lf), save=True)
lf.close()
I haven't faced similar problem but related issue. I have recently upgraded Django 1.8 to 1.11.
Now I am getting the following error if try to save a file in a model having FileField field:
SuspiciousFileOperation at /api/send_report/ The joined path (/vagrant/tmp/test_file.pdf) is located outside of the base path component (/vagrant/media)
My model where I want to save the file:
class Report(BaseModel):
file = models.FileField(max_length=200, upload_to=os.path.join(settings.REPORTS_URL, '%Y/week_%W/'))
type = models.CharField(max_length=20, verbose_name='Type', blank=False, default='', db_index=True)
I am trying following codes to save the file from tmp folder which is not located in MEDIA_ROOT:
from django.core.files import File
filepath = "/vagrant/tmp/test_file.pdf"
file = File(open(filepath, "rb"))
report_type = "My_report_type"
report = Report.objects.create(
file=file,
type=report_type,
)
What I have done to solve the issue:
import os
from django.core.files import File
filepath = "/vagrant/tmp/test_file.pdf"
file = File(open(filepath, "rb"))
file_name = os.path.basename(file.name)
report_type = "My_report_type"
report = Report.objects.create(
type=report_type,
)
report.file.save(file_name, file, save=True)
Hope it will help someone.
Analyzing this part of stacktrace:
File "C:\Python27\lib\site-packages\django\core\files\storage.py", line 261, in path
raise SuspiciousFileOperation("Attempted access to '%s' denied." % name)
leads to the standard Django FileSystemStorage
. It expects files to be within your MEDIA_ROOT
. Your files can be anywhere in the file system, therefore this problem occurs.
You should pass file-like object instead of a path to your File
model. The easiest way to achieve that would be to use Django File
class, which is a wrapper around python file-like objects. See File object documentation for more details.
Update:
Ok, I am suggesting here a route taken from the docs:
from django.core.files import File as FileWrapper
def _handle_directory(self, directory_path, directory):
for root, subFolders, files in os.walk(directory_path):
for filename in files:
self.cnt_files += 1
new_file = File(
directory=directory, filename=filename,
file=os.path.join(root, filename),
uploader=self.uploader)
with open(os.path.join(root, filename), 'r') as f:
file_wrapper = FileWrapper(f)
new_file = File(
directory=directory, filename=filename,
file=file_wrapper,
uploader=self.uploader)
new_file.save()
If it works it should copy the file to the location provided by your secure_storage
callable.