How to save a stream into multiple destinations with Gulp.js?

Currently you have to use two streams for each dest when using file.contents as a stream. This will probably be fixed in the future.

var gulp       = require('gulp');
var rename     = require('gulp-rename');
var streamify  = require('gulp-streamify');
var uglify     = require('gulp-uglify');
var source     = require('vinyl-source-stream');
var browserify = require('browserify');
var es         = require('event-stream');

gulp.task('scripts', function () {
    var normal = browserify('./src/index.js').bundle()
        .pipe(source('bundle.js'))
        .pipe(gulp.dest('./dist'));

    var min = browserify('./src/index.js').bundle()
        .pipe(rename('bundle.min.js'))
        .pipe(streamify(uglify())
        .pipe(gulp.dest('./dist'));

    return es.concat(normal, min);
});

EDIT: This bug is now fixed in gulp. The code in your original post should work fine.

I was facing similar issue and wanted the gulp source to be copied to multiple locations after lint, uglify and minify tasks. I ended up resolving this as below,

gulp.task('script', function() {
  return gulp.src(jsFilesSrc)
    // lint command
    // uglify and minify commands
    .pipe(concat('all.min.js'))
    .pipe(gulp.dest('build/js')) // <- Destination to one location
    .pipe(gulp.dest('../../target/build/js')) // <- Destination to another location
});