Solution 1:

You will have to iterate through them one by one; as far as I know there is no other way to do it.

However, you can make this more efficient by using a bounding box when you get the items from core data - this will reduce the number of objects that will be returned.

i.e. Something like

float latMax = wantedLat + 1;
float latMin = wantedLat - 1;
float lngMax = wantedLng + 1;
float lngMin = wantedLng - 1;
NSPredicate *predicate = [NSPredicate
    predicateWithFormat:@"lat > %f and lat < %f and lng > %f and lng < %f",
    latMin, latMax, lngMin, lngMax];

Though, depending on how much data you have and how closely it's spaced, you will want to use a different number than 1!

Sam

PS Also, I haven't taken into account the fact that longitude wraps!

Solution 2:

You can't use CoreData to find the nearest object, but might want to narrow down the query by using a bounding box. To find the nearest object, you might prefer to use simply the difference in lat/long which is considerably faster than calculating the actual distances.

I had a similar question:

CoreData: Find minimum of calculated property