What exactly is an "open generic type" in .NET? [duplicate]

Solution 1:

The C# language defines an open type to be a type that's either a type argument or a generic type defined with unknown type arguments:

All types can be classified as either open types or closed types. An open type is a type that involves type parameters. More specifically:

A type parameter defines an open type.

An array type is an open type if and only if its element type is an open type.

A constructed type is an open type if and only if one or more of its type arguments is an open type. A constructed nested type is an open type if and only if one or more of its type arguments or the type arguments of its containing type(s) is an open type.

A closed type is a type that is not an open type.

Therefore T, List<T>, and Dictionary<string,T>, and Dictionary<T,U> are all open types (T and U are type arguments) whereas List<int> and Dictionary<string,int> are closed types.

There's a related concept: An unbound generic type is a generic type with unspecified type arguments. An unbound type can't be used in expressions other than typeof() and you can't instantiate it or call its methods. For instance, List<> and Dictionary<,> are unbound types.

To clarify the subtle distinction between an open type and an unbound type:

class Program {
   static void Main() { Test<int>(); }
   static void Test<T>() {
      Console.WriteLine(typeof(List<T>)); // Print out the type name
   }
}

If you run this snippet, it'll print out

System.Collections.Generic.List`1[System.Int32]

which is the CLR name for List<int>. It's clear at runtime that the type argument is System.Int32. This makes List<T> a bound open type.

At runtime, you can use reflection to bind type arguments to unspecified type parameters of unbound generic types with the Type.MakeGenericType method:

Type unboundGenericList = typeof(List<>);
Type listOfInt = unboundGenericList.MakeGenericType(typeof(int));
if (listOfInt == typeof(List<int>))
     Console.WriteLine("Constructed a List<int> type.");

You can check whether a type is an unbound generic type (generic type definition) from which you can construct bound types with the Type.IsGenericTypeDefinition property:

Console.WriteLine(typeof(Dictionary<,>).IsGenericTypeDefinition); // True
Console.WriteLine(typeof(Dictionary<int,int>).IsGenericTypeDefinition); // False

To get the unbound type from a constructed type at runtime, you can use the Type.GetGenericTypeDefinition method.

Type listOfInt = typeof(List<int>);
Type list = listOfInt.GetGenericTypeDefinition(); // == typeof(List<>)

Note that for a generic type, you can either have a completely unbound type definition, or a completely bound definition. You can't bind some type parameters and leave others unbound. For instance, you can't have Dictionary<int,> or Dictionary<,string>.

Solution 2:

An "open generic type" is just a generic type that doesn't yet have its type specified (e.g., CargoCrate<T>). It becomes "closed" once a concrete type has been assigned (e.g. CargoCrate<Widget>).

For example, say you have something like this:

public class Basket<T> {
  T[] basketItems;
}

public class PicnicBlanket<T> {
  Basket<T> picnicBasket;   // Open type here. We don't know what T is.
}

                                 // Closed type here: T is Food.
public class ParkPicnicBlanket : PicnicBlanket<Food> {
}

Here, picnicBasket's type is open: nothing's yet been assigned to T. When you make a concrete PicnicBlanket with a specific type -- for example, by writing PicnicBlanket<Food> p = new PicnicBlanket<Food>() -- we now call it closed.

What exactly is an "open generic type" in .NET? [duplicate]

Solution 1:

Solution 2:

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