How to create bitmap from byte array?

Solution 1:

You'll need to get those bytes into a MemoryStream:

Bitmap bmp;
using (var ms = new MemoryStream(imageData))
{
    bmp = new Bitmap(ms);
}

That uses the Bitmap(Stream stream) constructor overload.

UPDATE: keep in mind that according to the documentation, and the source code I've been reading through, an ArgumentException will be thrown on these conditions:

stream does not contain image data or is null.
-or-
stream contains a PNG image file with a single dimension greater than 65,535 pixels.

Solution 2:

Guys thank you for your help. I think all of this answers works. However i think my byte array contains raw bytes. That's why all of those solutions didnt work for my code.

However i found a solution. Maybe this solution helps other coders who have problem like mine.

static byte[] PadLines(byte[] bytes, int rows, int columns) {
   int currentStride = columns; // 3
   int newStride = columns;  // 4
   byte[] newBytes = new byte[newStride * rows];
   for (int i = 0; i < rows; i++)
       Buffer.BlockCopy(bytes, currentStride * i, newBytes, newStride * i, currentStride);
   return newBytes;
 }

 int columns = imageWidth;
 int rows = imageHeight;
 int stride = columns;
 byte[] newbytes = PadLines(imageData, rows, columns);

 Bitmap im = new Bitmap(columns, rows, stride, 
          PixelFormat.Format8bppIndexed, 
          Marshal.UnsafeAddrOfPinnedArrayElement(newbytes, 0));

 im.Save("C:\\Users\\musa\\Documents\\Hobby\\image21.bmp");

This solutions works for 8bit 256 bpp (Format8bppIndexed). If your image has another format you should change PixelFormat .

And there is a problem with colors right now. As soon as i solved this one i will edit my answer for other users.

*PS = I am not sure about stride value but for 8bit it should be equal to columns.

And also this function Works for me.. This function copies 8 bit greyscale image into a 32bit layout.

public void SaveBitmap(string fileName, int width, int height, byte[] imageData)
        {

            byte[] data = new byte[width * height * 4];

            int o = 0;

            for (int i = 0; i < width * height; i++)
            {
                byte value = imageData[i];


                data[o++] = value;
                data[o++] = value;
                data[o++] = value;
                data[o++] = 0; 
            }

            unsafe
            {
                fixed (byte* ptr = data)
                {

                    using (Bitmap image = new Bitmap(width, height, width * 4,
                                PixelFormat.Format32bppRgb, new IntPtr(ptr)))
                    {

                        image.Save(Path.ChangeExtension(fileName, ".jpg"));
                    }
                }
            }
        }

Solution 3:

Can be as easy as:

var ms = new MemoryStream(imageData);
System.Drawing.Image image = Image.FromStream(ms);

image.Save("c:\\image.jpg");

Testing it out:

byte[] imageData;

// Create the byte array.
var originalImage = Image.FromFile(@"C:\original.jpg");
using (var ms = new MemoryStream())
{
    originalImage.Save(ms, ImageFormat.Jpeg);
    imageData = ms.ToArray();
}

// Convert back to image.
using (var ms = new MemoryStream(imageData))
{
    Image image = Image.FromStream(ms);
    image.Save(@"C:\newImage.jpg");
}

Solution 4:

In addition, you can simply convert byte array to Bitmap.

var bmp = new Bitmap(new MemoryStream(imgByte));

You can also get Bitmap from file Path directly.

Bitmap bmp = new Bitmap(Image.FromFile(filePath));