Pandas GroupBy.apply method duplicates first group
This is by design, as described here and here
The apply
function needs to know the shape of the returned data to intelligently figure out how it will be combined. To do this it calls the function (checkit
in your case) twice to achieve this.
Depending on your actual use case, you can replace the call to apply
with aggregate
, transform
or filter
, as described in detail here. These functions require the return value to be a particular shape, and so don't call the function twice.
However - if the function you are calling does not have side-effects, it most likely does not matter that the function is being called twice on the first value.
This "issue" has now been fixed: Upgrade to 0.25+
Starting from v0.25, GroupBy.apply()
will only evaluate the first group once. See GH24748.
What’s new in 0.25.0 (July 18, 2019): Groupby.apply
on DataFrame
evaluates first group only once
Relevant example from documentation:
pd.__version__
# '0.25.0.dev0+590.g44d5498d8'
df = pd.DataFrame({"a": ["x", "y"], "b": [1, 2]})
def func(group):
print(group.name)
return group
New behaviour (>=v0.25):
df.groupby('a').apply(func)
x
y
a b
0 x 1
1 y 2
Old behaviour (<=v0.24.x):
df.groupby('a').apply(func)
x
x
y
a b
0 x 1
1 y 2
Pandas still uses the first group to determine whether apply
can take a fast path or not. But at least it no longer has to evaluate the first group twice. Nice work, devs!
you can use for loop to avoid the groupby.apply duplicate first row,
log_sample.csv
guestid,keyword
1,null
2,null
2,null
3,null
3,null
3,null
4,null
4,null
4,null
4,null
my code snippit
df=pd.read_csv("log_sample.csv")
grouped = df.groupby("guestid")
for guestid, df_group in grouped:
print(list(df_group['guestid']))
df.head(100)
output
[1]
[2, 2]
[3, 3, 3]
[4, 4, 4, 4]