Listing files in a directory matching a pattern in Java [duplicate]

See File#listFiles(FilenameFilter).

File dir = new File(".");
File [] files = dir.listFiles(new FilenameFilter() {
    @Override
    public boolean accept(File dir, String name) {
        return name.endsWith(".xml");
    }
});

for (File xmlfile : files) {
    System.out.println(xmlfile);
}

Since Java 8 you can use lambdas and achieve shorter code:

File dir = new File(xmlFilesDirectory);
File[] files = dir.listFiles((d, name) -> name.endsWith(".xml"));

Since java 7 you can the java.nio package to achieve the same result:

Path dir = ...;
List<File> files = new ArrayList<>();
try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir, "*.{java,class,jar}")) {
    for (Path entry: stream) {
        files.add(entry.toFile());
    }
    return files;
} catch (IOException x) {
    throw new RuntimeException(String.format("error reading folder %s: %s",
    dir,
    x.getMessage()),
    x);
}

The following code will create a list of files based on the accept method of the FileNameFilter.

List<File> list = Arrays.asList(dir.listFiles(new FilenameFilter(){
        @Override
        public boolean accept(File dir, String name) {
            return name.endsWith(".exe"); // or something else
        }}));