z-index is canceled by setting transform(rotate)

Using transform property, z-index is canceled and appeared in the front. (When commenting out -webkit-transform, z-index is properly working in below code)

.test {
  width: 150px;
  height: 40px;
  margin: 30px;
  line-height: 40px;
  position: relative;
  background: white;
  -webkit-transform: rotate(10deg);
}

.test:after {
  width: 100px;
  height: 35px;
  content: "";
  position: absolute;
  top: 0;
  right: 2px;
  -webkit-box-shadow: 0 5px 5px #999;
  /* Safari and Chrome */
  -webkit-transform: rotate(3deg);
  /* Safari and Chrome */
  transform: rotate(3deg);
  z-index: -1;
}

<html>

<head>
  <title>transform</title>
  <link rel="stylesheet" type="text/css" href="transformtest.css">
</head>

<body>
  <div class="test">z-index is canceled.</div>
</body>

</html>

How do transform and z-index work together?

Let's walk through what is occurring. To start, note that z-index on positioned elements and transform by itself create new "stacking contexts" on elements. Here's what's going on:

Your .test element has transform set to something other than none, which gives it its own stacking context.

You then add a .test:after pseudo-element, which is a child of .test. This child has z-index: -1, setting the stack level of .test:after within the stacking context of .test Setting z-index: -1 on .test:after does not place it behind .test because z-index only has meaning within a given stacking context.

When you remove -webkit-transform from .test it removes its stacking context, causing .test and .test:after to share a stacking context (that of <html>) and making .test:after go behind .test. Note that after removing .test's -webkit-transform rule you can, once again, give it its own stacking context by setting a new z-index rule (any value) on .test (again, because it is positioned)!

So how do we solve your problem?

To get z-index working the way you expect, make sure that .test and .test:after share the same stacking context. The problem is that you want .test rotated with transform, but to do so means creating its own stacking context. Fortunately, placing .test in a wrapping container and rotating that will still allow its children to share a stacking context while also rotating both.

Here's what you started with: http://jsfiddle.net/fH64Q/
And here's a way you can get around the stacking-contexts and keep the rotation (note that the shadow gets a bit cut off because of .test's white background):

.wrapper {
    -webkit-transform: rotate(10deg);
}
.test {
       width: 150px;
       height: 40px;
       margin: 30px;
       line-height: 40px;
       position: relative;
       background: white;
}
.test:after {
       width: 100px;
       height: 35px;
       content: "";
       position: absolute;
       top: 0;
       right: 2px;
       -webkit-box-shadow: 0 5px 5px #999; /* Safari and Chrome */
       -webkit-transform: rotate(3deg); /* Safari and Chrome */
       transform: rotate(3deg);
       z-index: -1;
}

<div class="wrapper">
    <div class="test">z-index is canceled.</div>
</div>

There are other ways to do this, better ways even. I would probably make the "post-it" background the containing element and then put the text inside, that would probably be the easiest method and would reduce the complexity of what you have.

Check out this article for more details about z-index and stacking order, or the working W3C CSS3 spec on stacking context

Set the div you want to stay on top to position:relative

Had a similar problem where siblings were being transform: translate()'d and z-index wouldn't work.

Most straightforward solution is to set position: relative on all siblings, then z-index would work again.

Quick fix: You could just rotate the other element by 0 degrees as well.

I was facing the similar problem. What i did was, I added a wrapper div around the test and gave the transform property to the wrapper div.

.wrapper{
    transform: rotate(10deg);
}

here is the fiddle http://jsfiddle.net/KmnF2/16/

z-index is canceled by setting transform(rotate)

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