Newbetuts
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Prove that if a prime $p$ divides $5^n-2$ and $2^n-5$, then $p = 3$
prime-numbers
elementary-number-theory
divisibility
$\gcd(5^{65} - 2, 2^{65} - 5) = 12681 = 3^2 \cdot 1409$
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