How do I find my IP Address from the command line?

Use ipconfig getifaddr en1 for wireless, or ipconfig getifaddr en0 for ethernet.

ipconfig getifaddr en0 is default for the Wi-Fi network adapter.

Alternatively you can also do:

dig -4 TXT +short o-o.myaddr.l.google.com @ns1.google.com

Output, e.g.:

172.79.136.120

The following works for me on 10.8 and on 10.10 Yosemite.

ifconfig | grep "inet " | grep -Fv 127.0.0.1 | awk '{print $2}' 

If you find the above gives you more than one answer, save the following to a script, and run it instead

ip_address.sh

#!/usr/bin/env bash

dumpIpForInterface()
{
  IT=$(ifconfig "$1") 
  if [[ "$IT" != *"status: active"* ]]; then
    return
  fi
  if [[ "$IT" != *" broadcast "* ]]; then
    return
  fi
  echo "$IT" | grep "inet " | grep -v 127.0.0.1 | awk '{print $2}'
}

main()
{
  # snagged from here: https://superuser.com/a/627581/38941
  DEFAULT_ROUTE=$(route -n get 0.0.0.0 2>/dev/null | awk '/interface: / {print $2}')
  if [ -n "$DEFAULT_ROUTE" ]; then
    dumpIpForInterface "$DEFAULT_ROUTE"
  else
    for i in $(ifconfig -s | awk '{print $1}' | awk '{if(NR>1)print}')
    do 
      if [[ $i != *"vboxnet"* ]]; then
        dumpIpForInterface "$i"
      fi
    done
  fi
}

main

Just type curl ifconfig.me in the terminal.