Difference of keywords 'typename' and 'class' in templates?
Solution 1:
typename
and class
are interchangeable in the basic case of specifying a template:
template<class T>
class Foo
{
};
and
template<typename T>
class Foo
{
};
are equivalent.
Having said that, there are specific cases where there is a difference between typename
and class
.
The first one is in the case of dependent types. typename
is used to declare when you are referencing a nested type that depends on another template parameter, such as the typedef
in this example:
template<typename param_t>
class Foo
{
typedef typename param_t::baz sub_t;
};
The second one you actually show in your question, though you might not realize it:
template < template < typename, typename > class Container, typename Type >
When specifying a template template, the class
keyword MUST be used as above -- it is not interchangeable with typename
in this case (note: since C++17 both keywords are allowed in this case).
You also must use class
when explicitly instantiating a template:
template class Foo<int>;
I'm sure that there are other cases that I've missed, but the bottom line is: these two keywords are not equivalent, and these are some common cases where you need to use one or the other.
Solution 2:
For naming template parameters, typename
and class
are equivalent. §14.1.2:
There is no semantic difference between class and typename in a template-parameter.
typename
however is possible in another context when using templates - to hint at the compiler that you are referring to a dependent type. §14.6.2:
A name used in a template declaration or definition and that is dependent on a template-parameter is assumed not to name a type unless the applicable name lookup finds a type name or the name is qualified by the keyword typename.
Example:
typename some_template<T>::some_type
Without typename
the compiler can't tell in general whether you are referring to a type or not.
Solution 3:
While there is no technical difference, I have seen the two used to denote slightly different things.
For a template that should accept any type as T, including built-ins (such as an array )
template<typename T>
class Foo { ... }
For a template that will only work where T is a real class.
template<class T>
class Foo { ... }
But keep in mind that this is purely a style thing some people use. Not mandated by the standard or enforced by compilers
Solution 4:
- No difference
- Template type parameter
Container
is itself a template with two type parameters.
Solution 5:
This piece of snippet is from c++ primer book. Although I am sure this is wrong.
Each type parameter must be preceded by the keyword class or typename:
// error: must precede U with either typename or class
template <typename T, U> T calc(const T&, const U&);
These keywords have the same meaning and can be used interchangeably inside a template parameter list. A template parameter list can use both keywords:
// ok: no distinction between typename and class in a template parameter list
template <typename T, class U> calc (const T&, const U&);
It may seem more intuitive to use the keyword typename rather than class to designate a template type parameter. After all, we can use built-in (nonclass) types as a template type argument. Moreover, typename more clearly indicates that the name that follows is a type name. However, typename was added to C++ after templates were already in widespread use; some programmers continue to use class exclusively