MySQL: How to select records for this week?
I have table temp
with structure on sqlfiddle:
id(int 11 primary key)
name(varchar 100)
name2(varchar 100)
date(datetime)
I would like get record on this week, example if now 21.11.2013 i would like all rows on 18.11.2013 to 24.11.2013(on week)
Now I see next algorithm:
- obtain weekday
- calculate how many days ago was Monday
- calculate the date Monday
- calculate future date Sunday
- make a request on date
Tell me please, is exist a shorter algorithm (preferably in the query MySQL)?
ADD Question is: Why this query select record on date 17.11.2013(Sunday) - 23.11.2013(Saturday)
and how get records on date 18.11.2013(Monday) - 24.11.2013(Sunday)
?
query:
select * from temp
where yearweek(`date`) = yearweek(curdate())
Thanks!
Solution 1:
Use YEARWEEK()
:
SELECT *
FROM your_table
WHERE YEARWEEK(`date`, 1) = YEARWEEK(CURDATE(), 1)
Solution 2:
Use YEARWEEK
. If you use WEEKOFYEAR
you will get records of previous years also.
SELECT id, name, date
FROM table
WHERE YEARWEEK(date)=YEARWEEK(NOW());
Solution 3:
For selecting records of day, week and month use this way:
function my_func($time, $your_date) {
if ($time == 'today') {
$timeSQL = ' Date($your_date)= CURDATE()';
}
if ($time == 'week') {
$timeSQL = ' YEARWEEK($your_date)= YEARWEEK(CURDATE())';
}
if ($time == 'month') {
$timeSQL = ' Year($your_date)=Year(CURDATE()) AND Month(`your_date`)= Month(CURDATE())';
}
$Sql = "SELECT * FROM your_table WHERE ".$timeSQL
return $Result = $this->db->query($Sql)->result_array();
}