How to apply a function to a tuple?

Solution 1:

In Scala 2.8 and newer:

scala> def f (i : Int, j : Int) = i + j
f: (i: Int,j: Int)Int

// Note the underscore after the f
scala> val ff = f _
ff: (Int, Int) => Int = <function2>

scala> val fft = ff.tupled
fft: ((Int, Int)) => Int = <function1>

In Scala 2.7:

scala> def f (i : Int, j : Int) = i + j
f: (Int,Int)Int

// Note the underscore after the f
scala> val ff = f _
ff: (Int, Int) => Int = <function>

scala> val fft = Function.tupled(ff)
fft: ((Int, Int)) => Int = <function>

Solution 2:

Following up on the other answer, one could write (tested with 2.11.4):

scala> def f (i: Int, j: Int) = i + j
f: (i: Int, j: Int)Int

scala> val ff = f _
ff: (Int, Int) => Int = <function2>

scala> val p = (3,4)
p: (Int, Int) = (3,4)

scala> ff.tupled(p)
res0: Int = 7

See def tupled: ((T1, T2)) ⇒ R:

Creates a tupled version of this function: instead of 2 arguments, it accepts a single scala.Tuple2 argument.

Solution 3:

Scala 2.13

def f (i : Int, j : Int) = i + j

import scala.util.chaining._
(3,4).pipe((f _).tupled)   //res0: Int = 7