Get all unique values in a JavaScript array (remove duplicates)
I have an array of numbers that I need to make sure are unique. I found the code snippet below on the internet and it works great until the array has a zero in it. I found this other script here on Stack Overflow that looks almost exactly like it, but it doesn't fail.
So for the sake of helping me learn, can someone help me determine where the prototype script is going wrong?
Array.prototype.getUnique = function() {
var o = {}, a = [], i, e;
for (i = 0; e = this[i]; i++) {o[e] = 1};
for (e in o) {a.push (e)};
return a;
}
More answers from duplicate question:
- Remove duplicate values from JS array
Similar question:
- Get all non-unique values (i.e.: duplicate/more than one occurrence) in an array
Solution 1:
With JavaScript 1.6 / ECMAScript 5 you can use the native filter
method of an Array in the following way to get an array with unique values:
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);
console.log(unique); // ['a', 1, 2, '1']
The native method filter
will loop through the array and leave only those entries that pass the given callback function onlyUnique
.
onlyUnique
checks, if the given value is the first occurring. If not, it must be a duplicate and will not be copied.
This solution works without any extra library like jQuery or prototype.js.
It works for arrays with mixed value types too.
For old Browsers (<ie9), that do not support the native methods filter
and indexOf
you can find work arounds in the MDN documentation for filter and indexOf.
If you want to keep the last occurrence of a value, simply replace indexOf
with lastIndexOf
.
With ES6 this can be shorten to:
// usage example:
var myArray = ['a', 1, 'a', 2, '1'];
var unique = myArray.filter((v, i, a) => a.indexOf(v) === i);
console.log(unique); // unique is ['a', 1, 2, '1']
Thanks to Camilo Martin for hint in comment.
ES6 has a native object Set
to store unique values. To get an array with unique values you could now do this:
var myArray = ['a', 1, 'a', 2, '1'];
let unique = [...new Set(myArray)];
console.log(unique); // unique is ['a', 1, 2, '1']
The constructor of Set
takes an iterable object, like an Array, and the spread operator ...
transform the set back into an Array. Thanks to Lukas Liese for hint in comment.
Solution 2:
Updated answer for ES6/ES2015: Using the Set and the spread operator (thanks le-m), the single line solution is:
let uniqueItems = [...new Set(items)]
Which returns
[4, 5, 6, 3, 2, 23, 1]
Solution 3:
I split all answers to 4 possible solutions:
- Use object
{ }
to prevent duplicates - Use helper array
[ ]
- Use
filter + indexOf
- Bonus! ES6
Sets
method.
Here's sample codes found in answers:
Use object { }
to prevent duplicates
function uniqueArray1( ar ) {
var j = {};
ar.forEach( function(v) {
j[v+ '::' + typeof v] = v;
});
return Object.keys(j).map(function(v){
return j[v];
});
}
Use helper array [ ]
function uniqueArray2(arr) {
var a = [];
for (var i=0, l=arr.length; i<l; i++)
if (a.indexOf(arr[i]) === -1 && arr[i] !== '')
a.push(arr[i]);
return a;
}
Use filter + indexOf
function uniqueArray3(a) {
function onlyUnique(value, index, self) {
return self.indexOf(value) === index;
}
// usage
var unique = a.filter( onlyUnique ); // returns ['a', 1, 2, '1']
return unique;
}
Use ES6 [...new Set(a)]
function uniqueArray4(a) {
return [...new Set(a)];
}
And I wondered which one is faster. I've made sample Google Sheet to test functions. Note: ECMA 6 is not avaliable in Google Sheets, so I can't test it.
Here's the result of tests:
I expected to see that code using object { }
will win because it uses hash. So I'm glad that tests showed the best results for this algorithm in Chrome and IE. Thanks to @rab for the code.
Update 2020
Google Script enabled ES6 Engine. Now I tested the last code with Sets
and it appeared faster than the object method.