How to check the exit code of the last command in batch file?

Solution 1:

Test for a return code greater than or equal to 1:

if ERRORLEVEL 1 echo Error

or

if %ERRORLEVEL% GEQ 1 echo Error

or test for a return code equal to 0:

if %ERRORLEVEL% EQU 0 echo OK

You can use other commands such as GOTO where I show echo.

Solution 2:

This really works when you have: App1.exe calls -> .bat which runs --> app2.exe

App2 returns errorlevel 1... but you need to catch that in the .bat and re-raise it to app1... otherwise .bat eats the errorlevel and app1 never knows.

Method:

In .bat:

app2.exe
if %ERRORLEVEL% GEQ 1 EXIT /B 1

This is a check after app2 for errorlevel. If > 0, then the .bat exits and sets errorlevel to 1 for the calling app1.

Solution 3:

I had a batch script in Teamcity pipeline and it did not exit after it's child script did exit with code 1.

To fix the problem I added this string IF %ERRORLEVEL% NEQ 0 EXIT 1 after the child script call.

main-script.bat

...some code
call child-script.bat
IF %ERRORLEVEL% NEQ 0 EXIT 1
...some code

After the child script call exit result is saved to %ERRORLEVEL%. If it did exit with an error %ERRORLEVEL% would not be equal to 0 and in this case we exit with code 1 (error).