How to check the exit code of the last command in batch file?
Solution 1:
Test for a return code greater than or equal to 1:
if ERRORLEVEL 1 echo Error
or
if %ERRORLEVEL% GEQ 1 echo Error
or test for a return code equal to 0:
if %ERRORLEVEL% EQU 0 echo OK
You can use other commands such as GOTO
where I show echo
.
Solution 2:
This really works when you have: App1.exe calls -> .bat which runs --> app2.exe
App2 returns errorlevel 1... but you need to catch that in the .bat and re-raise it to app1... otherwise .bat eats the errorlevel and app1 never knows.
Method:
In .bat:
app2.exe
if %ERRORLEVEL% GEQ 1 EXIT /B 1
This is a check after app2 for errorlevel. If > 0, then the .bat exits and sets errorlevel to 1 for the calling app1.
Solution 3:
I had a batch script in Teamcity pipeline and it did not exit after it's child script did exit with code 1.
To fix the problem I added this string IF %ERRORLEVEL% NEQ 0 EXIT 1
after the child script call.
main-script.bat
...some code
call child-script.bat
IF %ERRORLEVEL% NEQ 0 EXIT 1
...some code
After the child script call exit result is saved to %ERRORLEVEL%
. If it did exit with an error %ERRORLEVEL%
would not be equal to 0 and in this case we exit with code 1 (error).