Create a new color drawable

Solution 1:

Since you're talking about hex you have to start with 0x and don't forget the opacity.

So basically: 0xFFFF6666

ColorDrawable cd = new ColorDrawable(0xFFFF6666);

You can also create a new colors.xml file into /res and define the colors like:

<?xml version="1.0" encoding="utf-8"?>
<resources>
    <color name="mycolor">#FF6666</color>
</resources>

and simply get the color defined in R.color.mycolor

getResources().getColor(R.color.mycolor)

Solution 2:

For using with ContextCompat and rehuse the color you can do something like this:

ColorDrawable colorDrawable = new ColorDrawable(ContextCompat.getColor(this, R.color.white));

Solution 3:

It should be like this...

ColorDrawable cd = new ColorDrawable(0xffff6666);

Note I used 8 hex digits, not 6 hex digit . which add to transparency

Solution 4:

By followingthe above advice,to be a summary of this question:

1. ColorDrawable colorDrawable = new ColorDrawable(Color.parseColor("#ce9b2c"));`

2. ColorDrawable colorDrawable = new ColorDrawable(0xFFCE9B2C); Note there is 8 hex digits, not 6 hex digit,which no work. Case all

3. ColorDrawable colorDrawable = new ColorDrawable(ContextCompat.getColor(mContext,R.color.default_color));

Selecting up to you!

Solution 5:

I think you have to use :

public static int parseColor (String colorString)

Added in API level 1 Parse the color string, and return the corresponding color-int. If the string cannot be parsed, throws an IllegalArgumentException exception. Supported formats are: #RRGGBB #AARRGGBB red, blue, green, black, white, gray, cyan, magenta, yellow, lightgray, darkgray, grey, lightgrey, darkgrey, aqua, fuschia, lime, maroon, navy, olive, purple, silver, teal