Python: My function returns "None" after it does what I want it to [duplicate]
Solution 1:
function return None
by default, so you should return backwards
explicitly
also, you can use a pythonic way to solve the problem:
letters[::-1]
Solution 2:
You can use a return statement to exit the function returning a value. If the function gets to the end without reaching a return statement, it will return None by default
def add1(x):
return x+1
def returnsNone():
pass
print(add1(2))
print(returnsNone())
Solution 3:
Every function returns something in Python. If you don't explicitly return a value, Python has your function return None
.
Your function doesn't actually return anything because print
prints to stdout, while return
actually returns a value. They may look the same in the REPL, but they're completely different.
So to fix your problem, return a value:
return backwards