jquery using ajax to send data and save in php [duplicate]

you can use following code :

var form = new FormData($('#form_step4')[0]);
form.append('view_type','addtemplate');
$.ajax({
    type: "POST",
    url: "savedata.php",
    data: form,
    cache: false,
    contentType: false,
    processData: false,
    success:  function(data){
        //alert("---"+data);
        alert("Settings has been updated successfully.");
        window.location.reload(true);
    }
});

where savedata.php is the file name in which you can do the the DB things

Hi i would start by adding a id to the form. and then either go with a onclick on the button element, or just define a click-event-handler for the button.

<form id="my_form">
       Name:<input type='text' name='name'>
       E-mail:<input type='text' name='email'>
       Gender:<select name='gender'>
       <option value='male'>male</option>
       <option value='female'>female</option>
       </select>
       Message:<textarea name='about'></textarea>
       <input type="button" value="Send" onclick="sendForm()"/>
 </form>

Then the jquery/ajax/js part.

 function sendForm(){
    $.ajax({
    type: "POST",
    url: "PAGE2.php",
    data: jQuery("#my_form").serialize(),
    cache: false,
    success:  function(data){
       /* alert(data); if json obj. alert(JSON.stringify(data));*/
    }
  });

}

Try this one:

 <form id="formId">
           Name:<input type='text' name='name'>
           E-mail:<input type='text' name='email'>
           Gender:<select name='gender'>
           <option value='male'>male</option>
           <option value='female'>female</option>
           </select>
           Message:<textarea name='about'></textarea>
           <input type="button" value="Send" onclick="save()"/>
     </form>

 <script type="javascript">

    function save(){
        var query = $('#formId').serialize();
        var url = 'savedata.php';
        $.post(url, query, function (response) {
         alert (response);
        });

    }
</script>

assign Id to your form... for now in my code i have given ID formId.. you can change this one as per your form name.