Create N-element constexpr array in C++11

Hello i'm learning C++11, I'm wondering how to make a constexpr 0 to n array, for example:

n = 5;

int array[] = {0 ... n};

so array may be {0, 1, 2, 3, 4, 5}

In C++14 it can be easily done with a constexpr constructor and a loop:

#include <iostream>

template<int N>
struct A {
    constexpr A() : arr() {
        for (auto i = 0; i != N; ++i)
            arr[i] = i; 
    }
    int arr[N];
};

int main() {
    constexpr auto a = A<4>();
    for (auto x : a.arr)
        std::cout << x << '\n';
}

Unlike those answers in the comments to your question, you can do this without compiler extensions.

#include <iostream>

template<int N, int... Rest>
struct Array_impl {
    static constexpr auto& value = Array_impl<N - 1, N, Rest...>::value;
};

template<int... Rest>
struct Array_impl<0, Rest...> {
    static constexpr int value[] = { 0, Rest... };
};

template<int... Rest>
constexpr int Array_impl<0, Rest...>::value[];

template<int N>
struct Array {
    static_assert(N >= 0, "N must be at least 0");

    static constexpr auto& value = Array_impl<N>::value;

    Array() = delete;
    Array(const Array&) = delete;
    Array(Array&&) = delete;
};

int main() {
    std::cout << Array<4>::value[3]; // prints 3
}

Based on @Xeo's excellent idea, here is an approach that lets you fill an array of

• constexpr std::array<T, N> a = { fun(0), fun(1), ..., fun(N-1) };
• where T is any literal type (not just int or other valid non-type template parameter types), but also double, or std::complex (from C++14 onward)
• where fun() is any constexpr function
• which is supported by std::make_integer_sequence from C++14 onward, but easily implemented today with both g++ and Clang (see Live Example at the end of the answer)
• I use @JonathanWakely 's implementation at GitHub (Boost License)

Here is the code

template<class Function, std::size_t... Indices>
constexpr auto make_array_helper(Function f, std::index_sequence<Indices...>) 
-> std::array<typename std::result_of<Function(std::size_t)>::type, sizeof...(Indices)> 
{
    return {{ f(Indices)... }};
}

template<int N, class Function>
constexpr auto make_array(Function f)
-> std::array<typename std::result_of<Function(std::size_t)>::type, N> 
{
    return make_array_helper(f, std::make_index_sequence<N>{});    
}

constexpr double fun(double x) { return x * x; }

int main() 
{
    constexpr auto N = 10;
    constexpr auto a = make_array<N>(fun);

    std::copy(std::begin(a), std::end(a), std::ostream_iterator<double>(std::cout, ", ")); 
}

Live Example