how to skip blank line while reading CSV file using python

This is my code i am able to print each line but when blank line appears it prints ; because of CSV file format, so i want to skip when blank line appears

import csv
import time

ifile = open ("C:\Users\BKA4ABT\Desktop\Test_Specification\RDBI.csv", "rb")
for line in csv.reader(ifile): 
    if not line: 
        empty_lines += 1 
        continue
    print line

Solution 1:

If you want to skip all whitespace lines, you should use this test: ' '.isspace().

Since you may want to do something more complicated than just printing the non-blank lines to the console(no need to use CSV module for that), here is an example that involves a DictReader:

#!/usr/bin/env python
# Tested with Python 2.7

# I prefer this style of importing - hides the csv module
# in case you do from this_file.py import * inside of __init__.py
import csv as _csv


# Real comments are more complicated ...
def is_comment(line):
    return line.startswith('#')


# Kind of sily wrapper
def is_whitespace(line):
    return line.isspace()


def iter_filtered(in_file, *filters):
    for line in in_file:
        if not any(fltr(line) for fltr in filters):
            yield line


# A dis-advantage of this approach is that it requires storing rows in RAM
# However, the largest CSV files I worked with were all under 100 Mb
def read_and_filter_csv(csv_path, *filters):
    with open(csv_path, 'rb') as fin:
        iter_clean_lines = iter_filtered(fin, *filters)
        reader = _csv.DictReader(iter_clean_lines, delimiter=';')
        return [row for row in reader]


# Stores all processed lines in RAM
def main_v1(csv_path):
    for row in read_and_filter_csv(csv_path, is_comment, is_whitespace):
        print(row)  # Or do something else with it


# Simpler, less refactored version, does not use with
def main_v2(csv_path):
    try:
        fin = open(csv_path, 'rb')
        reader = _csv.DictReader((line for line in fin if not
                                  line.startswith('#') and not line.isspace()),
                                  delimiter=';')
        for row in reader:
            print(row)  # Or do something else with it
    finally:
        fin.close()


if __name__ == '__main__':
    csv_path = "C:\Users\BKA4ABT\Desktop\Test_Specification\RDBI.csv"
    main_v1(csv_path)
    print('\n'*3)
    main_v2(csv_path)

Solution 2:

Instead of

if not line:

This should work:

if not ''.join(line).strip():

Solution 3:

my suggestion would be to just use the csv reader who can delimite the file into rows. Like this you can just check whether the row is empty and if so just continue.

import csv

with open('some.csv', 'r') as csvfile:

    # the delimiter depends on how your CSV seperates values
    csvReader = csv.reader(csvfile, delimiter = '\t')

    for row in csvReader:
        # check if row is empty
        if not (row):    
            continue