Receive JSON POST with PHP

Try;

$data = json_decode(file_get_contents('php://input'), true);
print_r($data);
echo $data["operacion"];

From your json and your code, it looks like you have spelled the word operation correctly on your end, but it isn't in the json.

EDIT

Maybe also worth trying to echo the json string from php://input.

echo file_get_contents('php://input');

If you already have your parameters set like $_POST['eg'] for example and you don't wish to change it, simply do it like this:

$_POST = json_decode(file_get_contents('php://input'), true);

This will save you the hassle of changing all $_POST to something else and allow you to still make normal post requests if you wish to take this line out.

It is worth pointing out that if you use json_decode(file_get_contents("php://input")) (as others have mentioned), this will fail if the string is not valid JSON.

This can be simply resolved by first checking if the JSON is valid. i.e.

function isValidJSON($str) {
   json_decode($str);
   return json_last_error() == JSON_ERROR_NONE;
}

$json_params = file_get_contents("php://input");

if (strlen($json_params) > 0 && isValidJSON($json_params))
  $decoded_params = json_decode($json_params);

Edit: Note that removing strlen($json_params) above may result in subtle errors, as json_last_error() does not change when null or a blank string is passed, as shown here: http://ideone.com/va3u8U

Use $HTTP_RAW_POST_DATA instead of $_POST.

It will give you POST data as is.

You will be able to decode it using json_decode() later.

Receive JSON POST with PHP

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