Python: can't assign to literal
My task is to write a program that asks the user to enter 5 names which it stores in a list. Next, it picks one of these names at random and declares that person as the winner. The only issue is that when I try to run it, it says can't assign to literal
.
This is my code:
import random
1=input("Please enter name 1:")
2=int(input('Please enter name 2:'))
3=int(input('Please enter name 3:'))
4=int(input('Please enter name 4:'))
5=int(input('Please enter name 5:'))
name=random.randint(1,6)
print('Well done '+str(name)+'. You are the winner!')
I have to be able to generate a random name.
The left hand side of the =
operator needs to be a variable. What you're doing here is telling python: "You know the number one? Set it to the inputted string.". 1
is a literal number, not a variable. 1
is always 1
, you can't "set" it to something else.
A variable is like a box in which you can store a value. 1
is a value that can be stored in the variable. The input
call returns a string, another value that can be stored in a variable.
Instead, use lists:
import random
namelist = []
namelist.append(input("Please enter name 1:")) #Stored in namelist[0]
namelist.append(input('Please enter name 2:')) #Stored in namelist[1]
namelist.append(input('Please enter name 3:')) #Stored in namelist[2]
namelist.append(input('Please enter name 4:')) #Stored in namelist[3]
namelist.append(input('Please enter name 5:')) #Stored in namelist[4]
nameindex = random.randint(0, 5)
print('Well done {}. You are the winner!'.format(namelist[nameindex]))
Using a for loop, you can cut down even more:
import random
namecount = 5
namelist=[]
for i in range(0, namecount):
namelist.append(input("Please enter name %s:" % (i+1))) #Stored in namelist[i]
nameindex = random.randint(0, namecount)
print('Well done {}. You are the winner!'.format(namelist[nameindex]))
Just adding 1 more scenario which may give the same error:
If you try to assign values to multiple variables, then also you will receive same error. For e.g.
In C (and many other languages), this is possible:
int a=2, b=3;
In Python:
a=2, b=5
will give error:
can't assign to literal
EDIT:
As per Arne's comment below, you can do this in Python for single line assignments in a slightly different way:
a, b = 2, 5
You are trying to assign to literal integer values. 1
, 2
, etc. are not valid names; they are only valid integers:
>>> 1
1
>>> 1 = 'something'
File "<stdin>", line 1
SyntaxError: can't assign to literal
You probably want to use a list or dictionary instead:
names = []
for i in range(1, 6):
name = input("Please enter name {}:".format(i))
names.append(name)
Using a list makes it much easier to pick a random value too:
winner = random.choice(names)
print('Well done {}. You are the winner!'.format(winner))