PDO with INSERT INTO through prepared statements [closed]

You should be using it like so

<?php
$dbhost = 'localhost';
$dbname = 'pdo';
$dbusername = 'root';
$dbpassword = '845625';

$link = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbusername, $dbpassword);

$statement = $link->prepare('INSERT INTO testtable (name, lastname, age)
    VALUES (:fname, :sname, :age)');

$statement->execute([
    'fname' => 'Bob',
    'sname' => 'Desaunois',
    'age' => '18',
]);

Prepared statements are used to sanitize your input, and to do that you can use :foo without any single quotes within the SQL to bind variables, and then in the execute() function you pass in an associative array of the variables you defined in the SQL statement.

You may also use ? instead of :foo and then pass in an array of just the values to input like so;

$statement = $link->prepare('INSERT INTO testtable (name, lastname, age)
    VALUES (?, ?, ?)');

$statement->execute(['Bob', 'Desaunois', '18']);

Both ways have their advantages and disadvantages. I personally prefer to bind the parameter names as it's easier for me to read.


I have just rewritten the code to the following:

    $dbhost = "localhost";
    $dbname = "pdo";
    $dbusername = "root";
    $dbpassword = "845625";

    $link = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbusername, $dbpassword);
    $link->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    $statement = $link->prepare("INSERT INTO testtable(name, lastname, age)
        VALUES(?,?,?)");

    $statement->execute(array("Bob","Desaunois",18));

And it seems to work now. BUT. if I on purpose cause an error to occur, it does not say there is any. The code works, but still; should I encounter more errors, I will not know why.