Set to dict Python

Use dict.fromkeys():

c = dict.fromkeys(s, 0)

Demo:

>>> s = {1,2,4,5,6}
>>> dict.fromkeys(s, 0)
{1: 0, 2: 0, 4: 0, 5: 0, 6: 0}

This works for lists as well; it is the most efficient method to create a dictionary from a sequence. Note all values are references to that one default you passed into dict.fromkeys(), so be careful when that default value is a mutable object.

Besides the method given by @Martijn Pieters, you can also use a dictionary comprehension like this:

s = {1,2,4,5,6}
d = {e:0 for e in s}

This method is slower than dict.fromkeys(), but it allows you to set the values in the dict to whatever you need, in case you don't always want it to be zero.

You can also use it to create lists, lists comprehensions are faster and more pythonic that the loop that you have in your question. You can learn more about comprehensions here: http://docs.python.org/2/tutorial/datastructures.html#list-comprehensions

This is also another way to do

s = {1,2,3,4,5}
dict([ (elem, 0) for elem in s ])

Set to dict Python

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