Check if string ends with one of the strings from a list

What is the pythonic way of writing the following code?

extensions = ['.mp3','.avi']
file_name = 'test.mp3'

for extension in extensions:
    if file_name.endswith(extension):
        #do stuff

I have a vague memory that the explicit declaration of the for loop can be avoided and be written in the if condition. Is this true?

Though not widely known, str.endswith also accepts a tuple. You don't need to loop.

>>> 'test.mp3'.endswith(('.mp3', '.avi'))
True

Just use:

if file_name.endswith(tuple(extensions)):

There is two ways: regular expressions and string (str) methods.

String methods are usually faster ( ~2x ).

import re, timeit
p = re.compile('.*(.mp3|.avi)$', re.IGNORECASE)
file_name = 'test.mp3'
print(bool(t.match(file_name))
%timeit bool(t.match(file_name)

792 ns ± 1.83 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

file_name = 'test.mp3'
extensions = ('.mp3','.avi')
print(file_name.lower().endswith(extensions))
%timeit file_name.lower().endswith(extensions)

274 ns ± 4.22 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)