plain C: opening a directory with fopen()
Solution 1:
From http://pubs.opengroup.org/onlinepubs/7908799/xsh/fopen.html:
The fopen() function will fail if:
[EISDIR] The named file is a directory and mode requires write access.
At least on Linux, if you try to fopen("dirname", "wb")
you get an EISDIR error. I also tried with a directory with d-------- access rights, and I still get EISDIR (and not EACCES.)
Solution 2:
Directories do not exist in the C99 standard (or the C2011 one). So by definition, fopen
-ing a directory is either implementation specific or undefined behavior.
fopen(3) can fail (giving a NULL
result). fseek(3) can also fail (by returning -1). And then you should preferably check errno(3) or use perror(3)
ftell
is documented to return a long
, and -1L
on failure. On 64 bits Linux this is 0xffffffffffffffff
.
You code should be instead
FILE* fd = fopen(argv[1], "rb");
if (!fd)
{ perror(argv[1]); exit(EXIT_FAILURE); };
if (fseek(fd, 0, SEEK_END)<0)
{ perror("fseek"); exit(EXIT_FAILURE); };
long flen = ftell(fd);
if (flen == -1L)
{ perror("ftell"); exit(EXIT_FAILURE); };
BTW, On Linux/Debian/Sid/AMD64 with libc-2.17 and 3.10.6 kernel, that codes runs ok when argv[1]
is /tmp
; surprizingly, flen
is LONG_MAX
i.e. 0x7fffffffffffffff
BTW, on Linux, directories are a special case of files. Use stat(2) on a file path (and fstat
on a file descriptor, perhaps obtained with fileno(3) from some FILE*
) to know more meta data about some file, including its "type" (thru its mode). You want opendir(3), readdir(3) & closedir(3) to operate on directory contents. See also inode(7).