Set android shape color programmatically

I am editing to make the question simpler, hoping that helps towards an accurate answer.

Say I have the following oval shape:

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="oval">
    <solid android:angle="270"
           android:color="#FFFF0000"/>
    <stroke android:width="3dp"
            android:color="#FFAA0055"/>
</shape>

How do I set the color programmatically, from within an activity class?

Note: Answer has been updated to cover the scenario where background is an instance of ColorDrawable. Thanks Tyler Pfaff, for pointing this out.

The drawable is an oval and is the background of an ImageView

Get the Drawable from imageView using getBackground():

Drawable background = imageView.getBackground();

Check against usual suspects:

if (background instanceof ShapeDrawable) {
    // cast to 'ShapeDrawable'
    ShapeDrawable shapeDrawable = (ShapeDrawable) background;
    shapeDrawable.getPaint().setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
} else if (background instanceof GradientDrawable) {
    // cast to 'GradientDrawable'
    GradientDrawable gradientDrawable = (GradientDrawable) background;
    gradientDrawable.setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
} else if (background instanceof ColorDrawable) {
    // alpha value may need to be set again after this call
    ColorDrawable colorDrawable = (ColorDrawable) background;
    colorDrawable.setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
}

Compact version:

Drawable background = imageView.getBackground();
if (background instanceof ShapeDrawable) {
    ((ShapeDrawable)background).getPaint().setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
} else if (background instanceof GradientDrawable) {
    ((GradientDrawable)background).setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
} else if (background instanceof ColorDrawable) {
    ((ColorDrawable)background).setColor(ContextCompat.getColor(mContext,R.color.colorToSet));
}

Note that null-checking is not required.

However, you should use mutate() on the drawables before modifying them if they are used elsewhere. (By default, drawables loaded from XML share the same state.)

A simpler solution nowadays would be to use your shape as a background and then programmatically change its color via:

view.background.setColorFilter(Color.parseColor("#343434"), PorterDuff.Mode.SRC_ATOP)

See PorterDuff.Mode for the available options.

UPDATE (API 29):

The above method is deprecated since API 29 and replaced by the following:

view.background.colorFilter = BlendModeColorFilter(Color.parseColor("#343434"), BlendMode.SRC_ATOP)

See BlendMode for the available options.

Do like this:

    ImageView imgIcon = findViewById(R.id.imgIcon);
    GradientDrawable backgroundGradient = (GradientDrawable)imgIcon.getBackground();
    backgroundGradient.setColor(getResources().getColor(R.color.yellow));

This question was answered a while back, but it can modernized by rewriting as a kotlin extension function.

fun Drawable.overrideColor(@ColorInt colorInt: Int) {
    when (this) {
        is GradientDrawable -> setColor(colorInt)
        is ShapeDrawable -> paint.color = colorInt
        is ColorDrawable -> color = colorInt
    }
}

Try this:

 public void setGradientColors(int bottomColor, int topColor) {
 GradientDrawable gradient = new GradientDrawable(Orientation.BOTTOM_TOP, new int[]  
 {bottomColor, topColor});
 gradient.setShape(GradientDrawable.RECTANGLE);
 gradient.setCornerRadius(10.f);
 this.setBackgroundDrawable(gradient);
 }

for more detail check this link this

hope help.

Set android shape color programmatically

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