Remove a tag using BeautifulSoup but keep its contents
Current versions of the BeautifulSoup library have an undocumented method on Tag objects called replaceWithChildren(). So, you could do something like this:
html = "<p>Good, <b>bad</b>, and <i>ug<b>l</b><u>y</u></i></p>"
invalid_tags = ['b', 'i', 'u']
soup = BeautifulSoup(html)
for tag in invalid_tags:
for match in soup.findAll(tag):
match.replaceWithChildren()
print soup
Looks like it behaves like you want it to and is fairly straightforward code (although it does make a few passes through the DOM, but this could easily be optimized.)
The strategy I used is to replace a tag with its contents if they are of type NavigableString
and if they aren't, then recurse into them and replace their contents with NavigableString
, etc. Try this:
from BeautifulSoup import BeautifulSoup, NavigableString
def strip_tags(html, invalid_tags):
soup = BeautifulSoup(html)
for tag in soup.findAll(True):
if tag.name in invalid_tags:
s = ""
for c in tag.contents:
if not isinstance(c, NavigableString):
c = strip_tags(unicode(c), invalid_tags)
s += unicode(c)
tag.replaceWith(s)
return soup
html = "<p>Good, <b>bad</b>, and <i>ug<b>l</b><u>y</u></i></p>"
invalid_tags = ['b', 'i', 'u']
print strip_tags(html, invalid_tags)
The result is:
<p>Good, bad, and ugly</p>
I gave this same answer on another question. It seems to come up a lot.
Although this has already been mentoned by other people in the comments, I thought I'd post a full answer showing how to do it with Mozilla's Bleach. Personally, I think this is a lot nicer than using BeautifulSoup for this.
import bleach
html = "<b>Bad</b> <strong>Ugly</strong> <script>Evil()</script>"
clean = bleach.clean(html, tags=[], strip=True)
print clean # Should print: "Bad Ugly Evil()"
I have a simpler solution but I don't know if there's a drawback to it.
UPDATE: there's a drawback, see Jesse Dhillon's comment. Also, another solution will be to use Mozilla's Bleach instead of BeautifulSoup.
from BeautifulSoup import BeautifulSoup
VALID_TAGS = ['div', 'p']
value = '<div><p>Hello <b>there</b> my friend!</p></div>'
soup = BeautifulSoup(value)
for tag in soup.findAll(True):
if tag.name not in VALID_TAGS:
tag.replaceWith(tag.renderContents())
print soup.renderContents()
This will also print <div><p>Hello there my friend!</p></div>
as desired.
You'll presumably have to move tag's children to be children of tag's parent before you remove the tag -- is that what you mean?
If so, then, while inserting the contents in the right place is tricky, something like this should work:
from BeautifulSoup import BeautifulSoup
VALID_TAGS = 'div', 'p'
value = '<div><p>Hello <b>there</b> my friend!</p></div>'
soup = BeautifulSoup(value)
for tag in soup.findAll(True):
if tag.name not in VALID_TAGS:
for i, x in enumerate(tag.parent.contents):
if x == tag: break
else:
print "Can't find", tag, "in", tag.parent
continue
for r in reversed(tag.contents):
tag.parent.insert(i, r)
tag.extract()
print soup.renderContents()
with the example value, this prints <div><p>Hello there my friend!</p></div>
as desired.