removing all options of select box except 1st option
I'm trying to empty select options when:
id "mClick" is selected, id's "sClick", "cClick" and "srClick" will be emptied.
id "sClick" is selected, id's "cClick" and "srClick" will be emptied.
id "cClick" is selected, id "srClick" will be emptied.
<form action="javascript:void(0);" method="POST" id="lForm">
<table>
<tr>
<td>
<select name="module" id="mClick">
<option value="">Select Mod</option>
<option value="1">Mod 1</option>
<option value="2">Mod 2</option>
<option value="3">Mod 3</option>
</select>
</td>
<td>
<select name="state" id="sClick">
<option value="">Select State</option>
<option value="1">State 1</option>
<option value="2">State 2</option>
</select>
</td>
<td>
<select name="city" id="cClick">
<option value="">Select City</option>
<option value="1">City 1</option>
<option value="2">City 2</option>
</select>
</td>
<td>
<select name="services" id="srClick">
<option value="">Select Services</option>
<option value="1">Services 1</option>
<option value="2">Services 2</option>
</select>
</td>
</tr>
</table>
in scenario 3, i used this function, but it deleted all, except the last select. Any idea's what i'm missing? Thanks
$('#lForm select[id!="mClick"] select[id!="sClick"] select[id!="cClick"] option[value!=""]').remove().end();
Solution 1:
Try this
yourSelect.find('option').not(':first').remove();
Solution 2:
I was looking for one line code, what I found after lots of research is the Simplest and Best one line code to remove everything except first.
JQuery,
$('#ddlId option:not(:first)').remove();
Solution 3:
you can use the greater than :gt()
selector of jQuery for this
$('#lForm select[id!="makeClick"] select[id!="stateClick"] select[id!="cityClick"] option:gt(0)').remove().end();
This will remove all options that are greater than 0
Solution 4:
You can use not(:first)
$('#lForm select[id!="makeClick"] select[id!="stateClick"] select[id!="cityClick"] option:not(:first)').remove().end();