How to run a python script from IDLE interactive shell?
Python3:
exec(open('helloworld.py').read())
If your file not in the same dir:
exec(open('./app/filename.py').read())
See https://stackoverflow.com/a/437857/739577 for passing global/local variables.
In deprecated Python versions
Python2 Built-in function: execfile
execfile('helloworld.py')
It normally cannot be called with arguments. But here's a workaround:
import sys
sys.argv = ['helloworld.py', 'arg'] # argv[0] should still be the script name
execfile('helloworld.py')
Deprecated since 2.6: popen
import os
os.popen('python helloworld.py') # Just run the program
os.popen('python helloworld.py').read() # Also gets you the stdout
With arguments:
os.popen('python helloworld.py arg').read()
Advance usage: subprocess
import subprocess
subprocess.call(['python', 'helloworld.py']) # Just run the program
subprocess.check_output(['python', 'helloworld.py']) # Also gets you the stdout
With arguments:
subprocess.call(['python', 'helloworld.py', 'arg'])
Read the docs for details :-)
Tested with this basic helloworld.py
:
import sys
if len(sys.argv) > 1:
print(sys.argv[1])
You can use this in python3:
exec(open(filename).read())
The IDLE shell window is not the same as a terminal shell (e.g. running sh
or bash
). Rather, it is just like being in the Python interactive interpreter (python -i
). The easiest way to run a script in IDLE is to use the Open
command from the File
menu (this may vary a bit depending on which platform you are running) to load your script file into an IDLE editor window and then use the Run
-> Run Module
command (shortcut F5).