How to print a query string with parameter values when using Hibernate
Is it possible in Hibernate to print generated SQL queries with real values instead of question marks?
How would you suggest to print queries with real values if it is not possible with Hibernate API?
You need to enable logging for the the following categories:
-
org.hibernate.SQL
- set todebug
to log all SQL DML statements as they are executed -
org.hibernate.type
- set totrace
to log all JDBC parameters
So a log4j configuration could look like:
# logs the SQL statements
log4j.logger.org.hibernate.SQL=debug
# Logs the JDBC parameters passed to a query
log4j.logger.org.hibernate.type=trace
The first is equivalent to hibernate.show_sql=true
legacy property, the second prints the bound parameters among other things.
Another solution (non hibernate based) would be to use a JDBC proxy driver like P6Spy.
Just for convenience, here is the same configuration example for Logback (SLF4J)
<appender name="SQLROLLINGFILE">
<File>/tmp/sql.log</File>
<rollingPolicy>
<FileNamePattern>logFile.%d{yyyy-MM-dd}.log</FileNamePattern>
</rollingPolicy>
<layout>
<Pattern>%-4date | %msg %n</Pattern>
</layout>
</appender>
<logger name="org.hibernate.SQL" additivity="false" >
<level value="DEBUG" />
<appender-ref ref="SQLROLLINGFILE" />
</logger>
<logger name="org.hibernate.type" additivity="false" >
<level value="TRACE" />
<appender-ref ref="SQLROLLINGFILE" />
</logger>
The output in your sql.log (example) then looks like this:
2013-08-30 18:01:15,083 | update stepprovider set created_at=?, lastupdated_at=?, version=?, bundlelocation=?, category_id=?, customer_id=?, description=?, icon_file_id=?, name=?, shareStatus=?, spversion=?, status=?, title=?, type=?, num_used=? where id=?
2013-08-30 18:01:15,084 | binding parameter [1] as [TIMESTAMP] - 2012-07-11 09:57:32.0
2013-08-30 18:01:15,085 | binding parameter [2] as [TIMESTAMP] - Fri Aug 30 18:01:15 CEST 2013
2013-08-30 18:01:15,086 | binding parameter [3] as [INTEGER] -
2013-08-30 18:01:15,086 | binding parameter [4] as [VARCHAR] - com.mypackage.foo
2013-08-30 18:01:15,087 | binding parameter [5] as [VARCHAR] -
2013-08-30 18:01:15,087 | binding parameter [6] as [VARCHAR] -
2013-08-30 18:01:15,087 | binding parameter [7] as [VARCHAR] - TODO
2013-08-30 18:01:15,087 | binding parameter [8] as [VARCHAR] -
2013-08-30 18:01:15,088 | binding parameter [9] as [VARCHAR] - [email protected]
2013-08-30 18:01:15,088 | binding parameter [10] as [VARCHAR] - PRIVATE
2013-08-30 18:01:15,088 | binding parameter [11] as [VARCHAR] - 1.0
2013-08-30 18:01:15,088 | binding parameter [12] as [VARCHAR] - 32
2013-08-30 18:01:15,088 | binding parameter [13] as [VARCHAR] - MatchingStep
2013-08-30 18:01:15,089 | binding parameter [14] as [VARCHAR] -
2013-08-30 18:01:15,089 | binding parameter [15] as [INTEGER] - 0
2013-08-30 18:01:15,089 | binding parameter [16] as [VARCHAR] - 053c2e65-5d51-4c09-85f3-2281a1024f64
If you are using Spring Boot, just config this:
application.yml
logging:
level:
org.hibernate.SQL: DEBUG
org.hibernate.type: TRACE
application.properties
logging.level.org.hibernate.SQL=DEBUG
logging.level.org.hibernate.type=TRACE
and nothing more.
Your log will be something like this:
2020-12-07 | DEBUG | o.h.SQL:127 - insert into Employee (id, name, title, id) values (?, ?, ?, ?)
2020-12-07 | TRACE | o.h.t.d.s.BasicBinder:64 - binding parameter [1] as [VARCHAR] - [001]
2020-12-07 | TRACE | o.h.t.d.s.BasicBinder:64 - binding parameter [2] as [VARCHAR] - [John Smith]
2020-12-07 | TRACE | o.h.t.d.s.BasicBinder:52 - binding parameter [3] as [VARCHAR] - [null]
2020-12-07 | TRACE | o.h.t.d.s.BasicBinder:64 - binding parameter [4] as [BIGINT] - [1]