How to split a string by spaces in a Windows batch file?

Solution 1:

Three possible solutions to iterate through the words of the string:

Version 1:

@echo off & setlocal
set s=AAA BBB CCC DDD EEE FFF
for %%a in (%s%) do echo %%a

Version 2:

@echo off & setlocal
set s=AAA BBB CCC DDD EEE FFF
set t=%s%
:loop
for /f "tokens=1*" %%a in ("%t%") do (
   echo %%a
   set t=%%b
   )
if defined t goto :loop

Version 3:

@echo off & setlocal
set s=AAA BBB CCC DDD EEE FFF
call :sub1 %s%
exit /b
:sub1
if "%1"=="" exit /b
echo %1
shift
goto :sub1

Version 1 does not work when the string contains wildcard characters like '*' or '?'.

Versions 1 and 3 treat characters like '=', ';' or ',' as word separators. These characters have the same effect as the space character.

Solution 2:

see HELP FOR and see the examples

or quick try this

 for /F %%a in ("AAA BBB CCC DDD EEE FFF") do echo %%c

Solution 3:

This is the only code that worked for me:

for /f "tokens=4" %%G IN ("aaa bbb ccc ddd eee fff") DO echo %%G

output:

ddd

Solution 4:

The following code will split a string with an arbitrary number of substrings:

@echo off
setlocal ENABLEDELAYEDEXPANSION

REM Set a string with an arbitrary number of substrings separated by semi colons
set teststring=The;rain;in;spain

REM Do something with each substring
:stringLOOP
    REM Stop when the string is empty
    if "!teststring!" EQU "" goto END

    for /f "delims=;" %%a in ("!teststring!") do set substring=%%a

        REM Do something with the substring - 
        REM we just echo it for the purposes of demo
        echo !substring!

REM Now strip off the leading substring
:striploop
    set stripchar=!teststring:~0,1!
    set teststring=!teststring:~1!

    if "!teststring!" EQU "" goto stringloop

    if "!stripchar!" NEQ ";" goto striploop

    goto stringloop
)

:END
endlocal

Solution 5:

easy

batch file:

FOR %%A IN (1 2 3) DO ECHO %%A

command line:

FOR %A IN (1 2 3) DO ECHO %A