What is the maximum length in chars needed to represent any double value?
When I convert an unsigned 8-bit int to string then I know the result will always be at most 3 chars (for 255) and for an signed 8-bit int we need 4 chars for e.g. "-128".
Now what I'm actually wondering is the same thing for floating-point values. What is the maximum number of chars required to represent any "double" or "float" value as a string?
Assume a regular C/C++ double (IEEE 754) and normal decimal expansion (i.e. no %e printf-formatting).
I'm not even sure if the really small number (i.e. 0.234234) will be longer than the really huge numbers (doubles representing integers)?
Solution 1:
The standard header <float.h>
in C, or <cfloat>
in C++, contains several constants to do with the range and other metrics of the floating point types. One of these is DBL_MAX_10_EXP
, the largest power-of-10 exponent needed to represent all double
values. Since 1eN
needs N+1
digits to represent, and there might be a negative sign as well, then the answer is
int max_digits = DBL_MAX_10_EXP + 2;
This assumes that the exponent is larger than the number of digits needed to represent the largest possible mantissa value; otherwise, there will also be a decimal point followed by more digits.
CORRECTION
The longest number is actually the smallest representable negative number: it needs enough digits to cover both the exponent and the mantissa. This value is -pow(2, DBL_MIN_EXP - DBL_MANT_DIG)
, where DBL_MIN_EXP
is negative. It's fairly easy to see (and prove by induction) that -pow(2,-N)
needs 3+N
characters for a non-scientific decimal representation ("-0."
, followed by N
digits). So the answer is
int max_digits = 3 + DBL_MANT_DIG - DBL_MIN_EXP
For a 64-bit IEEE double, we have
DBL_MANT_DIG = 53
DBL_MIN_EXP = -1023
max_digits = 3 + 53 - (-1023) = 1079
Solution 2:
According to IEEE 754-1985, the longest notation for value represented by double type, i.e.:
-2.2250738585072020E-308
has 24 chars.
Solution 3:
A correct source of information that goes into more detail than the IEEE-754 Specification are these lecture notes from UC Berkely on page 4, plus a little bit of DIY calculations. These lecture slides are also good for engineering students.
Recommended Buffer Sizes
| Single| Double | Extended | Quad |
|:-----:|:------:|:--------:|:-----:|
| 16 | 24 | 30 | 45 |
These numbers are based on the following calculations:
Maximum Decimal Count of the Integral Portion
| Single| Double | Extended | Quad |
|:-----:|:------:|:--------:|:-----:|
| 9 | 17 | 21 | 36 |
* Quantities listed in decimals.
Decimal counts are based on the formula: At most Ceiling(1 + NLog_10(2)) decimals, where N is the number of bits in the integral portion*.
Maximum Exponent Lengths
| Single| Double | Extended | Quad |
|:-----:|:------:|:--------:|:-----:|
| 5 | 5 | 7 | 7 |
* Standard format is `e-123`.
Fastest Algorithm
The fastest algorithm for printing floating-point numbers is the Grisu2 algorithm detailed in the research paper Printing Floating-point Numbers Quickly and Accurately. The best benchmark I could find can be found here.
Solution 4:
You can use snprintf()
to check how many chars you need.
snprintf()
returns the number of chars needed to print whatever is passed to it.
/* NOT TESTED */
#include <stdio.h>
#include <stdlib.h>
int main(void) {
char dummy[1];
double value = 42.000042; /* or anything else */
int siz;
char *representation;
siz = snprintf(dummy, sizeof dummy, "%f", value);
printf("exact length needed to represent 'value' "
"(without the '\\0' terminator) is %d.\n", siz);
representation = malloc(siz + 1);
if (representation) {
sprintf(representation, "%f", value);
/* use `representation` */
free(representation);
} else {
/* no memory */
}
return 0;
}
Note: snprintf()
is a C99 function. If a C89 compiler provides it as an extension, it may not do what the above program expects.
Edit:
Changed the link to snprintf()
to one that actually describes the functionality imposed by the C99 Standard; the description in the original link is wrong.
2013: Changed the link back to POSIX site which I prefer over the site of the first edit.