How can I rbind vectors matching their column names?

rbind does not check for column names when binding together vectors:

l = list(row1 = c(10, 20), row2 = c(20, 10))
names(l$row1) = c("A", "B")
names(l$row2) = c("B", "A")
l
$row1
 A  B 
10 20 

$row2
 B  A 
20 10 

rbind(l$row1, l$row2)
      A  B
[1,] 10 20
[2,] 20 10

How can I produce this matrix from a number of list elements, insuring the column names are correctly matched across rows:

      A  B
[1,] 10 20
[2,] 10 20

Solution 1:

It seems that in current versions of R (I have version 3.3.0), rbind has the capacity to to join two data sets with the same name columns even if they are in different order.

   df1 <- data.frame(a = c(1:5), c = c(LETTERS[1:5]),b=c(11:15))
   df2 <- data.frame(a = c(6:10), b = c(16:20),c=c(LETTERS[6:10]))
   rbind(df1,df2)
    a c  b
1   1 A 11
2   2 B 12
3   3 C 13
4   4 D 14
5   5 E 15
6   6 F 16
7   7 G 17
8   8 H 18
9   9 I 19
10 10 J 20

Solution 2:

smartbind() will match column names and tolerates missing ones:

library(gtools)
do.call(smartbind,l)
      A  B
row1 10 20
row2 10 20

Solution 3:

You can use match:

l <- list(row1 = setNames(1:3, c("A", "B", "C")),
          row2 = setNames(1:3, c("B", "C", "A")),
          row3 = setNames(1:3, c("C", "A", "B")))

do.call(rbind, lapply(l, function(x) x[match(names(l[[1]]), names(x))]))

The result:

     A B C
row1 1 2 3
row2 3 1 2
row3 2 3 1

Solution 4:

rbind will work if you first change each element of l to a data frame:

do.call("rbind", lapply(l, function(x) data.frame(as.list(x))))

      A  B
row1 10 20
row2 10 20

Solution 5:

do.call(rbind, lapply(l, function(row) row[order(names(row))]))