iterating over two values of a list at a time in python [duplicate]

I have a set like (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08) which I need to iterate over, like

    for x,y in (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
        print (x,y)

which would print

    669256.02 6117662.09
    669258.61 6117664.39
    669258.05 6117665.08

im on Python 3.3 btw

Solution 1:

You can use an iterator:

>>> lis = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> it = iter(lis)
>>> for x in it:
...     print (x, next(it))
...     
669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Solution 2:

>>> nums = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> for x, y in zip(*[iter(nums)]*2):
        print(x, y)


669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Solution 3:

The grouper example in the itertools recipes section should help you here: http://docs.python.org/library/itertools.html#itertools-recipes

from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

You would then it use like this:

for x, y in grouper(my_set, 2, 0.0):  # Use 0.0 to pad with a float
    print(x, y)