ValueError: invalid literal for int() with base 10: 'stop'
Solution 1:
The string passed to int()
should only contain digits:
>>> int("stop")
Traceback (most recent call last):
File "<ipython-input-114-e5503af2dc1c>", line 1, in <module>
int("stop")
ValueError: invalid literal for int() with base 10: 'stop'
A quick fix will be to use exception handling here:
def guessingGame():
global randomNum
global userScore
guessTry = 3
while True:
guess = input('Guess a Number between 1 - 10, You have 3 Tries, or Enter Stop: ')
try:
if int(guess) == randomNum:
print('Correct')
break
if int(guess) < randomNum:
print('Too Low')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if int(guess) > randomNum:
print('Too High')
guessTry = guessTry - 1
print('You have, ' + str(guessTry) + ' Guesses Left')
if guessTry == 0:
print('You have no more tries')
return
except ValueError:
#no need of str() here
if guess.lower() == 'stop':
break
guessingGame()
And you can use guess.lower() == 'stop'
to match any uppercase-lowercase combination of "stop":
>>> "Stop".lower() == "stop"
True
>>> "SToP".lower() == "stop"
True
>>> "sTOp".lower() == "stop"
True
Solution 2:
Here's a more pythonic (Python 3) version.
def guessing_game(random_num):
tries = 3
print("Guess a number between 1 - 10, you have 3 tries, or type 'stop' to quit")
while True:
guess = input("Your number: ")
try:
guess = int(guess)
except (TypeError, ValueError):
if guess.lower() == 'stop' :
return
else:
print("Invalid value '%s'" % guess)
continue
if guess == random_num:
print('Correct')
return
elif guess < random_num:
print('Too low')
else:
print('Too high')
tries -= 1
if tries == 0:
print('You have no more tries')
return
print('You have %s guesses left' % tries)