How to make the for each loop function in C++ work with a custom class
I'm new to C/C++ programming, but I've been programming in C# for 1.5 years now. I like C# and I like the List class, so I thought about making a List class in C++ as an exercise.
List<int> ls;
int whatever = 123;
ls.Add(1);
ls.Add(235445);
ls.Add(whatever);
The implementation is similar to any Array List class out there. I have a T* vector member where I store the items, and when this storage is about to be completely filled, I resize it.
Please notice that this is not to be used in production, this is only an exercise. I'm well aware of vector<T> and friends.
Now I want to loop through the items of my list. I don't like to use for(int i=0;i<n; i==). I typed for in the visual studio, awaited for Intellisense, and it suggested me this:
for each (object var in collection_to_loop)
{
}
This obviously won't work with my List implementation. I figured I could do some macro magic, but this feels like a huge hack. Actually, what bothers me the most is passing the type like that:
#define foreach(type, var, list)\
int _i_ = 0;\
##type var;\
for (_i_ = 0, var=list[_i_]; _i_<list.Length();_i_++,var=list[_i_])
foreach(int,i,ls){
doWork(i);
}
My question is: is there a way to make this custom List class work with a foreach-like loop?
Solution 1:
Firstly, the syntax of a for-each loop in C++ is different from C# (it's also called a range based for loop. It has the form:
for(<type> <name> : <collection>) { ... }
So for example, with an std::vector<int> vec, it would be something like:
for(int i : vec) { ... }
Under the covers, this effectively uses the begin() and end() member functions, which return iterators. Hence, to allow your custom class to utilize a for-each loop, you need to provide a begin() and an end() function. These are generally overloaded, returning either an iterator or a const_iterator. Implementing iterators can be tricky, although with a vector-like class it's not too hard.
template <typename T>
struct List
{
T* store;
std::size_t size;
typedef T* iterator;
typedef const T* const_iterator;
....
iterator begin() { return &store[0]; }
const_iterator begin() const { return &store[0]; }
iterator end() { return &store[size]; }
const_iterator end() const { return &store[size]; }
...
};
With these implemented, you can utilize a range based loop as above.
Solution 2:
Let iterable be of type Iterable.
Then, in order to make
for (Type x : iterable)
compile, there must be types called Type and IType and there must be functions
IType Iterable::begin()
IType Iterable::end()
IType must provide the functions
Type operator*()
void operator++()
bool operator!=(IType)
The whole construction is really sophisticated syntactic sugar for something like
for (IType it = iterable.begin(); it != iterable.end(); ++it) {
Type x = *it;
...
}
where instead of Type, any compatible type (such as const Type or Type&) can be used, which will have the expected implications (constness, reference-instead-of-copy etc.).
Since the whole expansion happens syntactically, you can also change the declaration of the operators a bit, e.g. having *it return a reference or having != take a const IType& rhs as needed.
Note that you cannot use the for (Type& x : iterable) form if *it does not return a reference (but if it returns a reference, you can also use the copy version).
Note also that operator++() defines the prefix version of the ++ operator -- however it will also be used as the postfix operator unless you explicitly define a postfix ++. The ranged-for will not compile if you only supply a postfix ++, which btw.can be declared as operator++(int) (dummy int argument).
Minimal working example:
#include <stdio.h>
typedef int Type;
struct IType {
Type* p;
IType(Type* p) : p(p) {}
bool operator!=(IType rhs) {return p != rhs.p;}
Type& operator*() {return *p;}
void operator++() {++p;}
};
const int SIZE = 10;
struct Iterable {
Type data[SIZE];
IType begin() {return IType(data); }
IType end() {return IType(data + SIZE);}
};
Iterable iterable;
int main() {
int i = 0;
for (Type& x : iterable) {
x = i++;
}
for (Type x : iterable) {
printf("%d", x);
}
}
output
0123456789
You can fake the ranged-for-each (e.g. for older C++ compilers) with the following macro:
#define ln(l, x) x##l // creates unique labels
#define l(x,y) ln(x,y)
#define for_each(T,x,iterable) for (bool _run = true;_run;_run = false) for (auto it = iterable.begin(); it != iterable.end(); ++it)\
if (1) {\
_run = true; goto l(__LINE__,body); l(__LINE__,cont): _run = true; continue; l(__LINE__,finish): break;\
} else\
while (1) \
if (1) {\
if (!_run) goto l(__LINE__,cont);/* we reach here if the block terminated normally/via continue */ \
goto l(__LINE__,finish);/* we reach here if the block terminated by break */\
} \
else\
l(__LINE__,body): for (T x = *it;_run;_run=false) /* block following the expanded macro */
int main() {
int i = 0;
for_each(Type&, x, iterable) {
i++;
if (i > 5) break;
x = i;
}
for_each(Type, x, iterable) {
printf("%d", x);
}
while (1);
}
(use declspec or pass IType if your compiler doesn't even have auto).
Output:
1234500000
As you can see, continue and break will work with this thanks to its complicated construction.
See http://www.chiark.greenend.org.uk/~sgtatham/mp/ for more C-preprocessor hacking to create custom control structures.
Solution 3:
That syntax Intellisense suggested is not C++; or it's some MSVC extension.
C++11 has range-based for loops for iterating over the elements of a container. You need to implement begin() and end() member functions for your class that will return iterators to the first element, and one past the last element respectively. That, of course, means you need to implement suitable iterators for your class as well. If you really want to go this route, you may want to look at Boost.IteratorFacade; it reduces a lot of the pain of implementing iterators yourself.
After that you'll be able to write this:
for( auto const& l : ls ) {
// do something with l
}
Also, since you're new to C++, I want to make sure that you know the standard library has several container classes.