How do I replace single quotes with double quotes in JavaScript?

Solution 1:

var a = "[{'column1':'value0','column2':'value1','column3':'value2'}]";
var b = a.replace(/'/g, '"');
console.log(b);

Edit: Removed \ as there are useless here.

Solution 2:

Need to use regex for this:

var a = "[{'column1':'value0','column2':'value1','column3':'value2'}]";
var b = a.replace(/\'/g, "\"");

http://jsfiddle.net/9b3K3/

Solution 3:

You can use a global qualifier (a trailing g) on a regular expression:

var b = a.replace(/'/g, '"');

Without the global qualifier, the regex (/'/) only matches the first instance of '.

Solution 4:

replaceAll(search, replaceWith) replaces ALL occurrences of search with replaceWith.

Then, make sure you have a string by wrapping one type of qoutes by different type:

 "a 'b' c".replaceAll("'", '"')
 // result: "a "b" c"
    
 "a 'b' c".replaceAll(`'`, `"`)
 // result: "a "b" c"

More about replaceAll

replaceAll (MDN): replaceAll(search, replaceWith)

It's actually the same as using replace() with a global regex(*), merely replaceAll() is a bit more readable in my view.

(*) Meaning it'll match all occurrences.

Example 1 - search with a string

const p = 'Please replace all 2020 occurrences with 2021. 2020. 2020.' 
   
console.log(p.replaceAll('2020', '2021'));
// Result: "Please replace all 2021 occurrences with 2021. 2021. 2021."

Example 2 - search with regex

const p = 'Please replace all 2020 occurrences with 2021. 2020. 2020.'    
const regex = /2020/gi


console.log(p.replaceAll(regex, '2021'));
// Result: "Please replace all 2021 occurrences with 2021. 2021. 2021."

Important(!) if you choose regex:

when using a regexp you have to set the global ("g") flag; otherwise, it will throw a TypeError: "replaceAll must be called with a global RegExp".

You can also use a function as replaceWith

In this case, the function will be invoked after the match has been performed. The function's result (return value) will be used as the replacement string.