How do I tell if the c function atoi failed or if it was a string of zeros?
When using the function atoi
(or strtol
or similar functions for that matter), how can you tell if the integer conversion failed or if the C-string that was being converted was a 0
?
For what I'm doing, 0
is an acceptable value and the C-string being converted may contain any number of 0
s. It may also have leading whitespace.
The proper function (as long as you are insisting on using C-style functions) is strtol
and the conversion code might look as follows
const char *number = "10"; /* for example */
char *end;
long value = strtol(number, &end, 10);
if (end == number || *end != '\0' || errno == ERANGE)
/* ERROR, abort */;
/* Success */
/* Add whatever range checks you want to have on the value of `value` */
Some remarks:
strtol
allows (meaning: quietly skips) whitespace in front of the actual number. If you what to treat such leading whitespace as an error, you have to check for it yourself.
The check for *end != '\0'
makes sure that there's nothing after the digits. If you want to permit other characters after the actual number (whitespace?), this check has to be modified accordingly.
P.S. I added the end == number
check later to catch empty input sequences. "All whitespace" and "no number at all" inputs would have been caught by *end != '\0'
check alone. It might make sense to catch empty input in advance though. In that case end == number
check will/might become unnecessary.
Since this is tagged c++:
template< typename T >
inline T convert(const std::string& str)
{
std::istringstream iss(str);
T obj;
iss >> std::ws >> obj >> std::ws;
if(!iss.eof())
throw "dammit!";
return obj;
}
For C++11 and later:
The go-to function for string-to-integer conversion is now stoi
, which takes a string
and returns an int
, or throws an exception on error.
No need for the verbose istringstream
hack mentioned in the accepted answer anymore.
(There's also stol
/stoll
/stof
/stod
/stold
for long
/long long
/float
/double
/long double
conversions, respectively.)