How can I get to Mars with a polynomial?
Solution 1:
We know that $(a,b)\in[0,0]\times [9,9]$ (since $a,b$ are single-digit integers. If negative numbers are considered "single-digit integers", too, then this is generalizable for those, too). So, what about $$p(x)=100(x-0)(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)$$ A plot made with Wolfram Mathematica 10.0:
So if you wanna go to Mars, this is probably a good polynomial to try.